What is the inverse of #f(x) = (x-3)/5#?

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Answer 1 · 2017-03-27T23:01:33

#f^-1(x)=5x+3#

Switch #x# for #y# and #f(x)# for #x#:

#x=(y-3)/5#

Solve for y. First, multiply by #5#:

#5x=5(y-3)/5#

#5x=y-3#

Now add #3# to both sides:

#5x+3=y#

Rewrite it so #y# is on the other side:

#y=5x+3#

Write #y# as #f^-1(x)#

#f^-1(x)=5x+3#