An object with a mass of #7 kg# is hanging from a spring with a constant of #3 (kg)/s^2#. If the spring is stretched by # 5 m#, what is the net force on the object?

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Answer 1 · 2017-03-28T07:26:05

The net force on the object is #=53.6N#

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Let's resolve in the vertical direction #uarr^+#

mass, #m=7kg#

spring constant, #k=3kgs^-2#

extension of the spring, #x=5m#

#F_1=kx=3*5=15N#

#F_2=-7g=-68.6N#

The net force is

#F=F_1+F_2=15-68.6=-53.6N#

The force is acting downwards.