Question

Question #02b23

Answer 1

`(x,y)=(-4/3,2/3)`

Explanation:

I've no idea what the leading `(-3,1)` means.

Since this was asked under the heading "Systems Using Substitution", I will demonstrate how to solve the given two equations (using substitution.

Given
[1]`color(white)("XXX")x-y=-2`
[2]`color(white)("XXX")x+5y=2`

Rewriting [1] as a definition in terms of `x`
[3]`color(white)("XXX")x=y-2`

We can now substitute `y-2` for `x` in equation [2]
[4]`color(white)("XXX")(y-2) +5y=2`

`rarr`[5]`color(white)("XXX")6y=4`

`rarr`[6]`color(white)("XXX")y=2/3`

Now substitute `2/3` for `y` in [1]
[7]`color(white)("XXX")x-2/3=-2`

`rarr`[8]`color(white)("XXX")x=-6/3+2/3=-4/3`