Question

How do you solve the inequality `x>=abs(x+1)` and write your answer in interval notation?

Answer 1

No feasible values for `x`

Explanation:

Considering `absx` for `x ne 0` we have

`x/absx ge abs((x+1)/x)` or

`pm 1 ge abs((x+1)/x)` or

`abs((x+1)/x) le min(-1,1) = -1`

So no solution for the inequality