How do you simplify #\frac { 2x } { x ^ { 2} - 16} + \frac { x } { x - 4}#?

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Answer 1 · 2017-03-29T22:58:37

#(6x+x^2)/(x^2-16)#

Multiply the right fraction with #(x+4)/(x+4#

#(2x)/(x^2-16) + (x(x+4))/(x^2-16)#

Let's only worry about the numerators. We have:

#2x+x(x+4)#

Distribute the #x# into the #x+4#:

#2x+x^2+4x#

Combine like terms:

#6x+x^2#

So our final answer is:

#(6x+x^2)/(x^2-16)#