Question

Question #9ebcd

Answer 1

Explanation below.

Explanation:

Strontium hydroxide or `SrOH_2` is a strong base and will completely ionize. This means that virtually all `SrOH_2` will dissociate in water into metal cations and hydroxide ions.

`"Sr"("OH")_2(s) -> "Sr"^{2+}+2"OH"^-`

`pOH` is the negative log of the concentration of hydroxide molecules. Since we know that `SrOH_2` will completely ionize in solution, we can use the given concentration to solve for `pOH`.

`pOH = -log [OH^-]`
`pOH = -log [2.0 * 10^-1 M]`
`pOH = 0.70`

The question asks for `pH` and not `pOH`. Using the formula below, we can solve for `pH`.

`pH + pOH = 14`
`pH + 0.70 = 14`
`pH = 14-0.70 = 13.3`
`pH = 13.3`

The `pH` is 13.3 at `"25 degrees Celsius"`