Question #036ed
2 Answers
The mixture would be water and sodium chloride at a concentration of .1 molar.
Explanation:
Sodium Hydroxide would neutralize the Hydrochloric acid.
Since the molar concentration of the Sodium Hydroxide would be .2 molar, the concentration of the Sodium ion would be .2 molar.
Since the molar concentration of the Hydrogen Chloride ( Hydrochloric acid) would be .2 molar the concentration of the Chlorine ion would be .2 molar.
These concentrations would be before the mixture. Since the mixture would have twice the volume of the initial solutions and the moles of the Sodium Chloride doesn't change the concentration of the solution of the mixture is half
The molar concentration of the salt water is .1 M
The mixed solution will consist of 500 mL of 0.2 mol/L
Explanation:
The equation for the reaction is
This looks like a limiting reactant problem, so we calculate the amount of
Identify the limiting reactant
From
From
Calculate the moles of
Calculate the moles of
Calculate the final concentrations of all substances
At the end of the reaction, we have 0.1 mol
in 500 mL solution.