How do you solve #-2x ( 2x + 3) = 0#?

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Answer 1 · 2017-03-31T19:40:36

#x=0, -3/2#

So we want to solve for #x# and since the question is already in the factored form we have little to do.

#-2x(2x+3)=0# is the same as #(-2x)(2x+3)=0#

All we do is to equate the first term to #0# and then the second also to #0#.

#-2x=0#

Divide both sides by #-2#

#(cancel(-2)x)/cancel(-2)=0/-2#

Zero divided by any number is #0#

#rArr#So, #x=0# for the first part.

Now to the second

#2x+3=0#

#2x=-3#

Dividing both sides by #2# we get

#(cancel(2)x)/cancel2=-3/2#

#x=-3/2#