Question

How do you write `log_216 36 = 2/3` in exponential form?

Answer 1

`216^(2/3)=36`

Explanation:

Okay, so we know that the base of a log is also the base of an exponent.

`a=x^b` is `log_xa=b`

Knowing this, let's write `log_(216)36=2/3` in exponential form.

`rArr216^(2/3)=36`