Question

Question #ec394

Answer 1

The limit does not exist.

Explanation:

As `xrarr5`, the numerator goes to `-25` and the denominator goes to `0`.

The denominator is negative for `xrarr5^-`, so

`lim_(xrarr5^-) (-x^2-5x+25)/(x-5) = oo`

The denominator is positive for `xrarr5^+`, so

`lim_(xrarr5^+) (-x^2-5x+25)/(x-5) = -oo`