Question

Question #b5ac6

Answer 1

Normal would be vertical line parallel to y axis, hence its slope would be undefined.

Explanation:

`dx/dt= -a sin t` and `dy/dt= a cos t`

this gives `dy/dx = - cost /sint`

At t= `90^o= pi/2`, `dy/dx= -0/1=0`

The slope at t= pi/2 is thus 0, that means the tangent is a horizontal line that is parallel to x axis.

The normal to this horizontal tangent would thus be a vertical line. Its slope would therefor be undefined,