First, multiply each side of the equation by #color(red)(16)# (this is the LCD of the two fractions) to eliminate the fractions while keeping the equation balanced:
#cancel(color(red)(16))8 xx (x + 5)/color(red)(cancel(color(black)(2))) = cancel(color(red)(16)) xx 38/color(red)(cancel(color(black)(16)))#
#8(x + 5) = 38#
#(8 xx x) + (8 xx 5) = 38#
#8x + 40 = 38#
Next, subtract #color(red)(40)# from each side of the equation to isolate the #x# term while keeping the equation balanced:
#8x + 40 - color(red)(40) = 38 - color(red)(40)#
#8x + 0 = -2#
#8x = -2#
Now, divide each side of the equation by #color(red)(8)# to solve for #x# while keeping the equation balanced:
#(8x)/color(red)(8) = -2/color(red)(8)#
#(color(red)(cancel(color(black)(8)))x)/cancel(color(red)(8)) = -2/color(red)(8)#
#x = -1/4#