How do you solve #(3r+9)/6 = (5r-10)/5#?

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Answer 1 · 2017-04-05T00:27:17

#r = 7#

Cross multiply,

#(3r+9)*5 = (5r-10)*6#

Expand,

#15r+45 = 30r-60#

Collect like terms

#15r = 105#

#r = 7#