Question

What is the amount of energy needed to heat 55.0 g of water from 45°C to 67°C?

Answer 1

5.8 kJ

Explanation:

Use the equation,

`Q=mcdeltaT`

where Q is heat flow (energy), m is mass, c is specific heat capcity and `deltaT` is the change in tempreture (`T2-T1`)

The specific heat capacity of water is `(4.816J/(g*C))`

`Q=(55.0 g)*(4.816J/(g*C))*(67 C -45C)`

Solve and the answer is,

5,827 J or 5.827 kJ

To 2 significant digits,

5.8 kJ