If you dilute a solution that has 2.95 liters of a 8 M down to 1.425 L, what is the new molarity?

1 Answer
anor277
Apr 5, 2017

The old equation is #C_1V_1=C_2V_2#

But I think you have worded the question improperly......

Explanation:

The product #"concentration"xx"volume"# has units of #"moles"#.........and given a dilution of a solute, of course the amount of solute will remain constant.

In this problem, #V_2# is apparently SMALLER than #V_1#; you have CONCENTRATED the solution by (somehow) removing the solvent. With water this would be a hard thing to do. Would you review this question?

Related questions
See all questions in Molarity
Impact of this question
1466 views around the world
You can reuse this answer
Creative Commons License