If you dilute a solution that has 2.95 liters of a 8 M down to 1.425 L, what is the new molarity?

1 Answer
anor277
Apr 5, 2017

The old equation is #C_1V_1=C_2V_2#

But I think you have worded the question improperly......

Explanation:

The product #"concentration"xx"volume"# has units of #"moles"#.........and given a dilution of a solute, of course the amount of solute will remain constant.

In this problem, #V_2# is apparently SMALLER than #V_1#; you have CONCENTRATED the solution by (somehow) removing the solvent. With water this would be a hard thing to do. Would you review this question?

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