How do you combine #\frac { 4u } { u ^ { 2} - 16} + \frac { 2} { u + 7} - \frac { 1} { u + 4}#?

Question

1098 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-05T07:46:45

#(5u^2+25u-4)/((u+4)(u-4)(u+7))#

#(4u)/(u^2-16)+(2)/(u+7)-(1)/(u+4)#

#=(4u)/((u+4)(u-4))+(2)/(u+7)-(1)/(u+4)#

#=(4u)/((u+4)(u-4))-(1)/(u+4)+(2)/(u+7)#

#=(4u)/((u+4)(u-4))-(u-4)/((u+4)(u-4))+(2)/(u+7)#

#=(4u-(u-4))/((u+4)(u-4))+2/(u+7)#

#=(3u+4)/((u+4)(u-4))+2/(u+7)#

#=((3u+4)(u+7))/((u+4)(u-4)(u+7))+(2(u-4)(u+4))/((u+7)(u-4)(u+4))#

#=((3u+4)(u+7)+2(u+4)(u-4))/((u+4)(u-4)(u+7))#

#=(3u^2+28+25u+2u^2-32)/((u+4)(u-4)(u+7))#

#=(5u^2+25u-4)/((u+4)(u-4)(u+7))#