Review this reaction: #H_2SO_4 + NaOH#. What are th product(s)?

1 Answer
rzp7
Apr 5, 2017

The products are #H_2O# and #Na_2SO_4#, since this is a double-replacement/neutralization reaction.

Explanation:

This is a double-replacement neutralization (acid-base) reaction:

The two #H# atoms in #H_2SO_4# would react with the hydroxide ion, #OH^-#, in #NaOH# to form water, #H_2O#.

The #SO_4# would react with #Na# to form #Na_2SO_4# .

# H_2SO_4+NaOH->H_2O +Na_2SO_4#

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