Question

What mass of sodium chloride is required in the following scenario?

A `350.00*L` volume of `NaCl(aq)` is required at `4.315*mol*L^-1` concentration. What mass of solute is required?

Answer 1

You would need over `88*kg` of salt........

Explanation:

`"Concentration"` `=` `"Moles of solute"/"Volume of solution"`.

And thus `"moles of solute"="concentration"xx"volume of solution"`

And the problem gives us 2 of these 3 quantities, we just have to multiply and divide.

`"moles of solute"=350.00*cancelLxx4.315*mol*cancel(L^-1)=1510.25*mol`.

And we then need to multiply this molar quantity by the molar mass of `NaCl` in `g*mol^-1`:

`1510.25*cancel(mol)xx(35.45+22.99)*g*cancel(mol^-1)=`

`??*g` of salt..........