An object with a mass of #7 kg# is hanging from a spring with a constant of #2 (kg)/s^2#. If the spring is stretched by # 19 m#, what is the net force on the object?

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Answer 1 · 2017-04-06T13:43:40

The net force is #=30.6N# acting downwards.

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Let's resolve in the vertical direction #uarr^+#

mass, #m=7kg#

spring constant, #k=2kgs^-2#

extension of the spring, #x=19m#

#F_1=kx=2*19=38N#

#F_2=-7g=-68.6N#

The net force is

#F=F_1+F_2=38-68.6=-30.6N#

The force is acting downwards.