Question

The length of rectangle is 5 more than the width. The perimeter is 22 feet. How do you find the length and width?

Answer 1

`W = 11/6 " ft" = 1 " ft " 10 " inches" = 22 " inches"`
`L = 9 " ft " 2 " inches" = 110 " inches"`

Explanation:

Given: `L = 5W`, Perimeter `= 22 " ft"`

Perimeter, `P = 2L + 2W`

Substitute in your given values:
`22 = 2(5W) + 2W`

Distribute and solve for `W`:

`22 = 10W + 2 W`
`22 = 12W`

`W = 22/12 = 11/6 " ft" = 1 " ft " 10 " inches" = 22 " inches"`

`L = 5W = 5*11/6 = 55/6 = 9 " ft " 2 " inches" = 110 " inches"`

Answer 2

length: 8
width: 3

Explanation:

`a`=length;
`b`=width;

`a=b+5` --> length is 5 more than the width

`22=2a+2b` --> div all by 2
`11=a+b`
`b=11-a`

`b=11-b-5`
`2b=6`

`b=3`
`a=b+5=3+5=8`

`2*8+2*3=16+6=22` --> CORRECT