How do you solve #-x + 5= - 2x + 11#?

1 Answer
smendyka
Apr 6, 2017

See the entire solution process below:

Explanation:

Subtract #color(red)(5)# and add #color(blue)(2x)# to each side of the equation to solve for #x# while keeping the equation balanced:

#color(blue)(2x) - x + 5 - color(red)(5) = color(blue)(2x) - 2x + 11 - color(red)(5)#

#color(blue)(2x) - 1x + 0 = 0 + 6#

#(color(blue)(2) - 1)x = 6#

#1x = 6#

#x = 6#

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