First, divide each side of the equation by #color(red)(1.2)# to eliminate the outer term on the left side of the equation while keeping the equation balanced:
#(1.2(2m - 2))/color(red)(1.2) = 15/color(red)(1.2)#
#(color(red)(cancel(color(black)(1.2)))(2m - 2))/cancel(color(red)(1.2)) = 12.5#
#2m - 2 = 12.5#
Next, add #color(red)(2)# to each side of the equation to isolate the #m# term while keeping the equation balanced:
#2m - 2 + color(red)(2) = 12.5 + color(red)(2)#
#2m - 0 = 14.5#
#2m = 14.5#
Now, divide each side of the equation by #color(red)(2)# to solve for #m# while keeping the equation balanced:
#(2m)/color(red)(2) = 14.5/color(red)(2)#
#(color(red)(cancel(color(black)(2)))m)/cancel(color(red)(2)) = 7.25#
#m = 7.25#
