How do you evaluate #(- 7) ^ { 2} \div ( - 3- - 10) ^ { 2}#?

Question

1024 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-06T22:01:11

First combine the terms in the parenthesis

# ( -7)^2 / {-3-(-10) }^2 = 49 /(+7)^2 #

a negative time a negative = a positive
# ( -7) xx ( -7) = + 49 #

# ( -) xx ( - 10) = + 10#

# -3 + 10 = +7#

# 49/(+7)^2 = 49/49#

# 49/49 = 1 #

Answer 2 · 2017-04-07T13:11:33

#1#

#(-7)^2-:(-3- -10)^2#

#color(white)(aaaaaaaaaaaaaa)##-3#
#color(white)(aaaaaaaaaaaaa)##-10# # -#
#color(white)(aaaaaaaaaaaaa)##---#
#color(white)(aaaaaaaaaaaaaa)##+7#

#:.(-7 xx -7)-:(7)^2#

#:.(-7 xx -7)-:7 xx 7#

#:.49-:49=1#