Circle A has a center at #(3 ,1 )# and a radius of #4 #. Circle B has a center at #(9 ,8 )# and a radius of #2 #. Do the circles overlap? If not what is the smallest distance between them?
1 Answer
no overlap, min distance
Explanation:
What we have to do here is
#color(blue)"compare"# the distance ( d ) between the centres of the circles to the#color(blue)"sum of radii"#
#• "If sum of radii "> d" then circles overlap"#
#• "If sum of radii "< d" then no overlap"# To calculate d use the
#color(blue)"distance formula"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(d=sqrt((x_2-x_1)^2+(y_2-y_1)^2))color(white)(2/2)|)))#
where# (x_1,y_1),(x_2,y_2)" are 2 coordinate points"#
#"the 2 points here are " (3,1)" and " (9,8)#
#"let " (x_1,y_1)=(3,1)" and " (x_2,y_2)=(9,8)#
#d=sqrt((9-3)^2+(8-1)^2)=sqrt(36+49)=sqrt85~~9.22#
#"sum of radii "=4+2=6#
#"since sum of radii "< d" then no overlap"#
#"min. distance between circles "=d-" sum of radii"#
#rArr"smallest distance "=9.22-6=3.22#
graph{(y^2-2y+x^2-6x-6)(y^2-16y+x^2-18x+141)=0 [-20, 20, -10, 10]}