How do you divide #(x ^ { 3} - 8x ^ { 2} + 17x - 10) \div ( x - 5)#?

1 Answer
Apr 10, 2017

The quotient is #=x^2-3x+2# and the remainder is #=0#

Explanation:

Let #f(x)=x^3-8x^2+17x-10#

Let's perform the synthetic division

#color(white)(aaaa)##5##color(white)(aaaaa)##|##color(white)(aaaa)##1##color(white)(aaaa)##-8##color(white)(aaaaa)##17##color(white)(aaa)##-10#
#color(white)(aaaaaaaaaaaa)#_________

#color(white)(aaaa)##color(white)(aaaaaaa)##|##color(white)(aaaa)##color(white)(aaaaaa)##5##color(white)(aaa)##-15##color(white)(aaaa)##10#
#color(white)(aaaaaaaaaaaa)#________

#color(white)(aaaa)##color(white)(aaaaaaa)##|##color(white)(aaaa)##1##color(white)(aaaa)##-3##color(white)(aaaaa)##2##color(white)(aaaaa)##color(red)(0)#

#f(x)=(x-5)(x^2-3x+2)#