Question

Question #10dc1

Answer 1

`=0.340` `mol`

Explanation:

Using the periodic table, the molar mass of `Fe(C_2H_3O_2)_3` is approximatly `232.98g/(mol)`

Using the molar mass and the grams given, you can solve for moles,

`79.3g*1/232.98(mol)/g`

`79.3cancelg*1/232.98(mol)/cancelg`

`79.3/232.98mol`

`=0.340` `mol`

Or you could of used the equation,

`n=m/(mm)`

Where `n` is moles, `m` is mass in `grams` and `mm` is molar mass in `(grams)/(mol)`