First, multiply each side of the equation by #color(red)(5)/color(blue)(2)# to eliminate the term outside the parenthesis while keeping the equation balanced:
#color(red)(5)/color(blue)(2) xx 2/5(2x + 6) = color(red)(5)/color(blue)(2) xx 4#
#cancel(color(red)(5))/cancel(color(blue)(2)) xx color(blue)(cancel(color(black)(2)))/color(red)(cancel(color(black)(5)))(2x + 6) = 20/2#
#2x + 6 = 10#
Next, subtract #color(red)(6)# from each side of the equation to isolate the #x# term while keeping the equation balanced:
#2x + 6 - color(red)(6) = 10 - color(red)(6)#
#2x + 0 = 4#
#2x = 4#
Now, divide each side of the equation by #color(red)(2)# to solve for #x# while keeping the equation balanced:
#(2x)/color(red)(2) = 4/color(red)(2)#
#(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = 2#
#x = 2#
