A balanced lever has two weights on it, the first with mass $8 k g$ $8 kg$ and the second with mass $64 k g$ $64 kg$ . If the first weight is $12 m$ $12 m$ from the fulcrum, how far is the second weight from the fulcrum?

Question

1344 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-13T07:14:46

The distance is $= 1.5 m$ $=1.5m$

enter image source here

The first weight is $M_{2} = (8 g) N$ $M_2=(8g)N$

The second weight is $M_{1} = (64 g) N$ $M_1=(64g)N$

The first distance is $b = 12 m$ $b=12m$

Taking moments about the fulcrum

$M_{1} \cdot a = M_{2} \cdot b$ $M_1*a=M_2*b$

$a = \frac{M_{2} \cdot b}{M_{1}} = \frac{8 g \cdot 12}{64 g} = 1.5 m$ $a=(M_2*b)/M_1=(8g*12)/(64g)=1.5m$

A balanced lever has two weights on it, the first with mass 8kg8 kg and the second with mass 64kg64 kg. If the first weight is 12m 12 m from the fulcrum, how far is the second weight from the fulcrum?