The standard form of a linear equation is: color(red)(A)x + color(blue)(B)y = color(green)(C)Ax+By=C
Where, if at all possible, color(red)(A)A, color(blue)(B)B, and color(green)(C)Care integers, and A is non-negative, and, A, B, and C have no common factors other than 1
First, subtract color(red)(12x)12x from each side of the equation to place both the xx and yy term on the left side of the equation as required by the standard form:
-color(red)(12x) + y = -color(red)(12x) + 12x−12x+y=−12x+12x
-12x + y = 0−12x+y=0
Because the xx coefficient must be positive we will multiply each side of the equation by color(red)(-1)−1:
color(red)(-1)(-12x + y) = color(red)(-1) xx 0−1(−12x+y)=−1×0
(color(red)(-1) xx -12x) + (color(red)(-1) xx y) = 0(−1×−12x)+(−1×y)=0
color(red)(12)x - color(blue)(1)y = color(green)(0)12x−1y=0
color(red)(A = 12)A=12
color(blue)(B = -1)B=−1
color(green)(C = 0)C=0