How do you solve #\frac { - 11+ x } { 16} < - 1#?

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Answer 1 · 2017-04-13T18:54:22

See the entire solution process below:

First, multiply each side of the inequality by #color(red)(16)# to eliminate the fraction while keeping the inequality balanced:

#color(red)(16) * (-11 + x)/16 < color(red)(16) * -1#

#cancel(color(red)(16)) * (-11 + x)/color(red)(cancel(color(black)(16))) < -16#

#-11 + x < -16#

Now, add #color(red)(11)# to each side of the inequality to solve for #x# while keeping the inequality balanced:

#color(red)(11) - 11 + x < color(red)(11) - 16#

#0 + x < -5#

#x < -5#