How do you solve lnx^2=1?

1 Answer
Apr 13, 2017

x=+-sqrt(e)

Or written using fractional exponents x=+-e^(1/2)

Explanation:

Rewrite both sides in terms of the base e

e^(ln(x^2))=e^1

x^2=e

take square root of both sides

x=+-sqrt(e)