Question

How do you solve `lnx^2=1`?

Answer 1

`x=+-sqrt(e)`

Or written using fractional exponents `x=+-e^(1/2)`

Explanation:

Rewrite both sides in terms of the base `e`

`e^(ln(x^2))=e^1`

`x^2=e`

take square root of both sides

`x=+-sqrt(e)`