Question

Four consecutive numbers have a sum of 234. What are the four numbers?

Answer 1

57, 58, 59 and 60

Explanation:

Let the first number be x. Then the next 3 consecutive numbers are x+1, x+2 and x+3.

As per questions, `x+(x+1)+(x+2)+(x+3) = 234`

`rArr 4x +6 = 234`

`rArr 4x = 234 - 6`

`rArr 4x = 228`

`rArr x = 228/4 = 57`

Hence the four numbers are 57, 58, 59 and 60

Answer 2

57, 58, 59, 60

Explanation:

Because we know the numbers are consecutive, the next number will always be 1 more than the previous and we also know they equal 234

Let's assign the unknown number `x`

and each consecutive number will be `x + 1, x+2` etc

So,

`(x) +(x+1)+(x+2)+(x+3) = 234`

Then algebra

`(x) +(x+1)+(x+2)+(x+3) = 234` - Simplify
`4x + 6 = 234` - Subtract 6 from each side
`4x = 228` - Divide by four
`x = 57`

We now know the first number out of the four and all you have to do is go up by 1 for the next three