How do you write #5y=10x-25# in standard form and what is A, B, C?

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Answer 1 · 2017-04-14T16:33:32

#-10x + 5y +25= 0

General form or standard form is #Ax + By + C = 0#

So #5y = 10x - 25# in standard form:

#-10x + 5y +25 = 0#

Where #A = -10, B = 5, C = 25#

Answer 2 · 2017-04-14T16:41:12

#2x-y=5# , where #A=2, B=-1 and C=5#

The standard form of the equation of a straight line is:

#Ax+By=C#, where #A>0#, and if possible #A, B and C# are relatively prime integers. Hence in this case:

#5y=10x-25#
#10x-5y=25#, can be written as:
#2x-y=5# => in standard form.