How do you write $1/2x + y = 3$ in standard form?

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Answer 1 · 2017-04-14T18:16:17

$y = -1/2x +3$

For this equation, the standard form is $y = mx + c$ . We have to rearrange our equation, $1/2x + y = 3$ , so it fits this standard form.

We are looking to have only $y$ on one side of the equation, and then a number multiplied by $x$ , then another number added on the other side.

Luckily, it is not too complicated in this case. We can simply subtract $1/2x$ from both sides of the equation, giving:

$y = 3 - 1/2x$

we can rearrange this to give

$y = -1/2x + 3$

This fits our standard form, $y = mx + c$ . This means that in this case, $m = -1/2$ , and $c = 3$

Answer 2 · 2017-04-14T18:35:55

$1x+2y=6$

My understanding of "standard form" for a linear equation is
$color(white)("XXX")Ax+By=C$
with integer constant values for $A, B, C$ and $A>=0$

Multiplying both sides of the given equation by $2$ gives the answer above.

How do you write 1/2x + y = 31/2x + y = 3 in standard form?