How do you differentiate # g(x) = 2 csc ^2x + 5 cos x #?

1 Answer
Apr 14, 2017

#g'(x)=-4csc^2(x)cot(x)-5sin(x)#

Explanation:

It helps to know some trig derivatives:

tutorial.math.lamar.edu

We're also going to need product rule since there's a #csc^2x#. Rewrite #g(x)#:

#g(x)=2csc(x)csc(x)+5cos(x)#

Now take the derivative with product rule:

#g'(x)=-2csc^2(x)cot(x)-2csc^2(x)cot(x)-5sin(x)#

Simplify:

#g'(x)=-4csc^2(x)cot(x)-5sin(x)#