Question

In 5 minutes, a seal descended 24 feet. What was the average rate of change in the seal's elevation per minute?

Answer 1

1.92 feet/minutes

Explanation:

We know, `s = ut +1/2ft^2` [where s = distance covered, t = time and

f = acceleration ]

here, u = 0, s = 24 feet, t = 5 minutes and f = ?

So, `24 = 0 + 1/2 xx f xx 5^2`

`rArr f = [24xx2]/25` feet/minute

`rArr f = 1.92` feet/minutes