Question

What is the moment of inertia of a pendulum with a mass of `2 kg` that is `12 m` from the pivot?

Answer 1

MOMENT OF INERTIA = `MR^2`

Explanation:

moment of inertia is defined as : `intdmr^2`
where dm is the mass of the differential element of the body and r is the distance of that differential element from the point about which you want to find out the moment of inertia .
thus , moment of inertia of a pendulum is = `mr^2`
m - mass of the bob
r - distance of bob from the pivot
with the assumption that the string connecting bob and the pivot is massless and inextensible .
therefore , moment of inertia = `2 * 12^2`
`= 288 kgm^2`