First, multiply each side of the equation by the common denominator of the two fractions which is #color(red)(40)color(blue)(z)#. This will eliminate the fractions while keeping the equation balanced:
#color(red)(40)color(blue)(z) xx 36/z = color(red)(40)color(blue)(z) xx 16/40#
#color(red)(40)cancel(color(blue)(z)) xx 36/color(blue)(cancel(color(black)(z))) = cancel(color(red)(40))color(blue)(z) xx 16/color(red)(cancel(color(black)(40)))#
#1440 = 16z#
Now, we can divide each side of the equation by #color(red)(16)# to solve for #z# while keeping the equation balanced:
#1440/color(red)(16) = (16z)/color(red)(16)#
#90 = (color(red)(cancel(color(black)(16)))z)/cancel(color(red)(16))#
#90 = z#
#z = 90#
Another method to solve for #z# is to "flip" the two fractions and then solve for #z#. Flipping the fractions gives:
#z/36 = 40/16#
Now, multiply each side of the equation by #color(red)(36)# to solve for #z# while keeping the equation balanced:
#color(red)(36) xx z/36 = color(red)(36) xx 40/16#
#cancel(color(red)(36)) xx z/color(red)(cancel(color(black)(36))) = 1440/16#
#z = 90#