Question

What volume of `"lithium sulfite solution"` of `2.50*mol*L^-1` concentration would contain a mass of `422.55*g`?

Answer 1

`"Moles of lithium sulfite req'd..........."=(422.55*g)/(93.94*g*mol^-1)=`

Explanation:

`=(422.55*g)/(93.94*g*mol^-1)=4.50*mol`.

And since `"concentration"="moles"/"volume"`, we need the quotient..........

`"volume"="moles"/"concentration"=(4.50*mol)/(2.50*mol*L^-1)=1.80*1/L^-1`

`1.80*1/(1/L)=1.80*L`

In practice, water is quite an involatile material. You would not evaporate this quantity of water.