Question

Let `f(x) = x+8` and `g(x)=x^2-6x-7`, what is `f(g(2))`?

Answer 1

`f(g(2))=-7`

Explanation:

Plug in `2` into `g(x)`

`g(2)=2^2-6(2)-7=-15`

Now that we have `g(2)=-15`, we can plug that into `f(x)`

`f(g(2))=f(-15)=-15+8=-7`