How do you solve #-17\geq 9x + 10#?

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Answer 1 · 2017-04-18T16:37:17

#x<=-3#

Subtract #10# on both sides:

#-17-10>=9x+10-10#

#-27>=9x#

Divide #9# on both sides:

#-27/9>=x#

#-3>=x#

I like #x# on the left side so I'm going to rewrite it as:

#x<=-3#