Question

What are the `x`-intercepts of `y=x^2-4x`?

Answer 1

`x= 0 and x = 4`

Explanation:

To find the `x` intercept of the equation `y=x^2-4x`, we input `y=0`, as at the `x` intercept the `y` co-ordinate will be zero.

We get,

`x^2-4x=0`
`x^2=4x`
`x=4`

`x=0` is an obvious answer.

graph{x^2-4x [-3.54, 6.46, -4.22, 0.78]}