Question #fc03e

1 Answer
Apr 19, 2017

#y=3/2x-3#

Standard form: move x and y to the same side, including any coefficients to the variables
#y-3/2x=-3#
#y-3/2x+3=0#
For the table of values, plug in x values into the given equation or look at the graph below
graph{3/2x-3 [-10, 10, -5, 5]}

For the second problem, look at the graph and find the slope, which is rise over run, or #(Delta y)/(Delta x)#.
graph{3/4x+3}
The graph has a slope of #3/4#, and the y intercept is at #(0,3)#. The slope intercept form of the graph is:
#y=3/4x+3#

Standard Form:
#y-3/4x=3#
#y-3/4x-3=0#

For the third problem, given the table of values, we can determine that the slope is #-1/3# because #"every 1 unit that "x" decreases, "y" decreases by "1/3#.
The #y# intercept is #-1# because there is a given point #(0,-1)#.

Slope intercept form:
#y=-1/3x-1#
Standard form:
#y+1/3x=-1#
#y+1/3x+1=0#
graph{y=-1/3x-1}