What is the specific latent heat for ice?....Take a look at details below..?

A pupil adds 37 g of ice at 0^oC to 100 g of water at 30^oC. The final temperature of water and ice is 0^oC. No heat is lost or gained from the surroundings.

The specific heat capacity of water ios 4.2 J/g^oC.

What is the specific latent heat for ice?

A 47 J/g

B 341 J/g

C 4700 J/g

D 12600 J/g

1 Answer
Apr 22, 2017

B

Explanation:

Assuming that in the final mixture of ice and water, all the ice is melted and becomes water at 0^@"C"

Heat gained by ice at 0^@"C" to water at 0^@"C" =Q_"gained"=m_"ice"L
where L is latent heat of ice.
:.Q_"gained"=37L" J" ......(1)

Heat lost by water at 30^@"C" to water at 0^@"C" =Q_"lost"=m_"water"xxsxxDeltaT
Inserting varius values we get
Q_"lost"=100xx4.2xx(30-0)
=>Q_"lost"=100xx4.2xx(30-0)=12600" J" ......(2)

Using Law of conservation of energy and equating (1) and (2) we get
37L=12600
=>L=12600/37
=>L=340.5" Jg"^-1