How do you multiply #(8x - 2) ( x - 4)#?

1 Answer
Jim G.
Apr 24, 2017

#8x^2-34x+8#

Explanation:

Each term in the second bracket is multiplied by each term in the first bracket as shown below.

#(color(red)(8x-2))#(x-4)

#=color(red)(8x)(x-4)color(red)(-2)(x-4)#

#=(color(red)(8x)xxx)+(color(red)(8x)xx-4)+(color(red)(-2)xxx)+(color(red)(-2)xx-4)#

#=8x^2+(-32x)+(-2x)+8#

#=8x^2-32x-2x+8#

#=8x^2-34x+8#

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