How do you solve # \frac { 1} { x } + \frac { 1} { 6} = \frac { 1} { 2}#?

1 Answer
Apr 24, 2017

See the solution process below:

Explanation:

First, subtract #color(red)(1/6)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#1/x + 1/6 - color(red)(1/6) = 1/2 - color(red)(1/6)#

#1/x + 0 = (3/3 xx 1/2) - color(red)(1/6)#

#1/x = (3 xx 1)/(3 xx 2) - color(red)(1/6)#

#1/x = 3/6 - color(red)(1/6)#

#1/x = (3 - 1)/6#

#1/x = 2/6#

#1/x = (2 xx 1)/(2 xx 3)#

#1/x = (cancel(2) xx 1)/(cancel(2) xx 3)#

#1/x = 1/3#

Now, multiply each side of the equation by #3x# to eliminate the fractions and solve for #x# while keeping the equation balanced:

#3x * 1/x = 3x * 1/3#

#3color(red)(cancel(color(black)(x))) * 1/color(red)(cancel(color(black)(x))) = color(blue)(cancel(color(black)(3)))x * 1/color(blue)(cancel(color(black)(3)))#

#3 * 1 = x * 1#

#3 = x#

#x = 3#