How do you solve #\frac { 1} { 2} x + 2x \cdot ( x - 4) = x - 1#?

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Answer 1 · 2017-04-24T22:26:05

#x=-((-4.5)+-sqrt(28.25))/4#

Distribute the #2x#:

#(1/2)x + 2x^2-4x=x-1#

Combine like terms on the left side:

#2x^2-3.5x=x-1#

Move everything to the left side:

#2x^2-4.5x-1=0#

#x=-((-4.5)+-sqrt((-4.5)^2-4(2)(-1)))/(2(2))#

Solve inside the square root and denominator:

#x=-((-4.5)+-sqrt(28.25))/4#