How do you solve #- 4( 3x - 2) = - 32#?

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Answer 1 · 2017-04-24T23:23:52

#x = 10/3#

Order of operations.
Multiply first.

#- 4( 3x - 2) = - 32#

#- 12x + 8 = - 32#

Move #8# to the other sign of the equation so we can begin to isolate #x#

#- 12x = - 32-8#

#- 12x = - 40#

Divide both sides by #-12# to get the value of #x#

#(cancel(- 12)x)/cancel(-12) = (- 40)/(-12)#

#x = 40/12#

Take out common factor #4#

#x = (cancel4(10))/(cancel4(3))#

#x = 10/3#