Question

If there are `56*L` of ozone, what molar quantity is present under standard conditions?

Answer 1

Well, if it is pure ozone, there are approx. `2.5*mol` of `O_3(g)`.

Explanation:

Under standard conditions of temperature and pressure, `273*K`, and `1*atm`, one mole of ideal gas occupies `22.4*L`.

And thus we calculate the quotient..........

`(56*L)/(22.4*L*mol^-1)=??*mol`

Note that ozone is a trace atmospheric gas, and you cannot get a bottle of ozone, as you would get a bottle of dioxygen, dinitrogen, etc.