How do you find a standard form equation for the line with (0,3),(-5,0)?

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Answer 1 · 2017-04-25T20:00:05

#3x-5y=-5#
#"Or "#
#y=3/5 x+3#

#(y-y_1)/(x-x_1)=(y_2-y)/(x_2-x)#

#A(x_1,y_1)=(0,3)#
#B(x_2,y_2)=(-5,0)#

#(y-3)/(x-0)=(0-y)/(-5-x)#

#(y-3)/(x)=(-y)/(-5-x)#

#-x y=(y-3)(-5-x)#

#-x y=-5 y-y x+15+3x#

#"rearrange "#

#3x-5y-cancel(y x)+cancel(y x)=-15#

#3x-5y=-15#

#"Or"#

#5y=3x+15#

#y=3/5 x+3#